When the elevator stops, the two forces are equal and opposite, and the net force is zero. But if you are accelerating upward, the net force must also be upward. This means that the normal force is greater than the force of gravity (shown by the length of the two arrows above). So you feel As the normal force increases, your weight becomes heavier. We can call the normal force your “apparent weight.”
See? You’re in this box and it seems like nothing is changing, but you feel like you’re being pulled downward by a more powerful gravity. That’s because your frame of referenceThe elevator car, which appears to be motionless, is actually moving upward. Basically, we are looking at how You Look inside the system to see how someone Outside The system sees it.
Could you build an elevator on the moon and accelerate it fast enough to get your weight back to Earth? Theoretically, yes. This is what Einstein’s equivalence principle says: there is no difference between a gravitational field and an accelerated reference frame.
A circuitous solution
But you understand the problem: to maintain upward momentum for a few minutes, the elevator shaft would have to be absurdly high, and you would soon reach an equally ridiculous speed. But wait! There is another way to generate acceleration: move in a circle.
Here’s a physics riddle for you: What are the three controls in a car that make it accelerate? Answer: The gas pedal (to speed up), the brake (to slow down), and the steering wheel (to change direction). Yes, these are all acceleration!
Remember, acceleration is the rate of change of velocity, and the main thing is this: velocity is a vector in physicsIt has a magnitude, which we call its speed, but it also has a specific direction. Turn the car and you’re accelerating, even though your speed is unchanged.
So what if you’re just driving in a circle? Then you’re constantly accelerating without going anywhere. This is called centripetal acceleration (AC), Meaning Center-direction: An object moving in a circle accelerates towards the centre, and the magnitude of this acceleration depends on the speed (V) and radius (R,